4x^2+14x=140

Solution for 4x^2+14x=140 equation:

4x^2+14x=140

We move all terms to the left:

4x^2+14x-(140)=0

a = 4; b = 14; c = -140;
Δ = b2-4ac
Δ = 142-4·4·(-140)
Δ = 2436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2436}=\sqrt{4*609}=\sqrt{4}*\sqrt{609}=2\sqrt{609}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{609}}{2*4}=\frac{-14-2\sqrt{609}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{609}}{2*4}=\frac{-14+2\sqrt{609}}{8}
$